How much solar energy (kJ) would have to be transferred to a 167.0 foot length of asphalt highway that is 44.5 feet wide and 23.9 centimeters deep in order to raise the temperature 1.50 oC ?The average density of asphalt is 721 kg/m3The specific heat of asphalt is 0.920 kJ/kg- oC

RONALD E B167 ft x 0.3048 m/ft = 50.90 m

44.5 ft x 0.3048 m/ft = 13.56 m

23.9 cm / 100 cm/m = 0.239 m

50.90 x 13.56 x 0.239 = 165 m^3

165 m^3 x 721 kg/m^3 = 118965 kg

118965 kg x 0.920 kJ/kg C x 1.50 C = 164000 kJ